Question

Find the dimensions, the width is 60 Area=240-400x sq yds

Answer 1

To find the length of a rectangle with a given width and area expressed as an equation, one must rearrange the area formula to solve for length, then substitute the known values and solve the equation.

Step-by-step explanation:

When working with dimensions and areas in mathematics, one fundamental concept is utilizing given values to determine the dimensions of shapes. Given the width and an equation for the area, we can solve for the length.

The student's question involves a rectangle where the width w is given as 60 yards and the area A is given by the equation A = 240 - 400x square yards. To find the length l, we can rearrange the equation to solve for l:

A = l × w

Substituting the known values:

240 - 400x = l × 60

To find the length l, divide both sides of the equation by 60:

l = × ×(240 - 400x) / 60

This calculation gives us the length in terms of x. If additional information about the value of x is provided, we can determine a specific value for the length. However, without knowing x, we can only express the length as a function of x.

Answer 2

The dimensions are (4 - 6.67x) yards by 60 yards.

Step-by-step explanation:

The area of a rectangle given by the equation A = LW, where L is the length and W is the width of the rectangle.

⇒
`L = (A)/(W)` ............. (1)

Now, the width is given by 60 yards i.e. W = 60 and the area is given by (240 - 400x) sq. yards i.e. A = 240 - 400x.

Therefore, from equation (1) we get,

`L = (A)/(W) = (240 - 400x)/(60) = 4 - 6.67x`

Therefore, the dimensions are (4 - 6.67x) yards by 60 yards. (Answer)