For this case we have the following system of equations:
![y = x + 3\\3x + y = 19](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8ht67no71bx8wt8scieduvcgu598v79qtk.png)
We solve by the substitution method:
We substitute the first equation in the second equation:
![3x + x + 3 = 19](https://img.qammunity.org/2021/formulas/mathematics/middle-school/68dbply3tuyrif3vjyrzd40zzz5doydhoa.png)
We add similar terms:
![4x + 3 = 19](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9ga3rc9pmsteewiy8hy70rh0j3k12d1yma.png)
We subtract 3 from both sides of the equation:
![4x = 19-3\\4x = 16](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jk50b4h2gwzgeaw75wux5kcpw4jb03jqt5.png)
We divide between 4 on both sides of the equation:
![x = \frac {16} {4}\\x = 4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/v905xqij70s9si1k6fa4ltaw98zqfalqx5.png)
We look for the value of the variable y:
![y=x+3\\y=4+3\\y=7](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4o49qkqzq0am1dcj0u554mzv6b37md96yd.png)
Finally, the solution of the system is:
![(x, y) :( 4,7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/22lo74n419pnpxdlnfgy939hk6u5uyslov.png)
Answer:
![(x, y) :( 4,7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/22lo74n419pnpxdlnfgy939hk6u5uyslov.png)