The cost of one apple is 50 cents and cost of 1 banana is 35 cents and cost of 1 orange is 25 cents
Solution:
Let "a" be the cost of 1 apple
Let "b" be the cost of 1 banana
Let "r" be the cost of 1 orange
Given that Apple costs the same as 2 oranges
cost of 1 apple = 2 (cost of 1 orange)
a = 2r -------- eqn 1
Together, an orange and a banana cost 10 cents more than an apple
cost of 1 orange + cost of 1 banana = 10 + cost of 1 apple
r + b = 10 + a --------- eqn 2
Two oranges cost 15 cents more that a banana
cost of 2 orange = 15 + cost of 1 banana
2r = 15 + b ----- eqn 3
Let us solve eqn 1, eqn 2 and eqn 3
From eqn 1 and eqn 3, substitute eqn 1 in eqn 3
a = b + 15 --- eqn 4
Substitute eqn 4 in eqn 2
r + b = 10 + b + 15
r = 10 + 15
r = 25
Substitute r = 25 in eqn 3
2(25) = 15 + b
50 - 15 = b
b = 35
Substitute b = 35 in eqn 4
a = 35 + 15
a = 50
Thus cost of one apple is 50 cents and cost of 1 banana is 35 cents and cost of 1 orange is 25 cents