Answer:
option A
Step-by-step explanation:
given,
Kinetic energy of the car = 2000 J
speed of the car is doubled
we know,
![KE_1 = (1)/(2)mv^2](https://img.qammunity.org/2021/formulas/physics/college/d6ahf19ab1jxhao2fvnuc94h5lspf37t2f.png)
........(1)
now, speed of the car is doubled
v' = 2 v
![KE_2 = (1)/(2)mv'^2](https://img.qammunity.org/2021/formulas/physics/college/eo3hpquht3gd0yw9i9e9099girtpouhjkh.png)
![KE_2 = (1)/(2)m(2v)^2](https://img.qammunity.org/2021/formulas/physics/college/qaav0b1sukkr866rwqabbed1aab2e1lgrb.png)
from equation (1)
![KE_2 = 4* (1)/(2)m(v)^2](https://img.qammunity.org/2021/formulas/physics/college/dualcuyr3sgth5b0mnhxilq565nu5slsi1.png)
![KE_2 = 4* 2000](https://img.qammunity.org/2021/formulas/physics/college/kbwhifl01lw2iydik0ez2deuihr8y0u4qi.png)
![KE_2 = 8000\ J](https://img.qammunity.org/2021/formulas/physics/college/5xyw72ohmnmcafhpzpr1dquxwtwm8xd8xe.png)
Hence, the Kinetic energy would be equal to 8000 J.
The correct answer is option A.