Question

A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s. What is the car’s change in momentum due to this collision?A. 2.3x 10^4 kg·m/s towards the wall B. 2.3x 10^4 kg·m/s away from the wall C. 1.7 x 10^4 kg·m/s away from the wall D. 1.7 x 10^4 kg·m/s towards the wall Impulse

Answer 1

The car's change in momentum due to the collision is 17550 kg·m/s towards the wall.

Step-by-step explanation:

Change in momentum is calculated using the formula:

Δp = mΔv

Where:

Δp is the change in momentum

m is the mass of the car

Δv is the change in velocity

Using the given values:

Δp = (700 kg)(4.5 m/s - 29 m/s)

Δp = -17550 kg·m/s

Since the car rebounds with a speed of 4.5 m/s, it means the direction of velocity is reversed. Therefore, the car's change in momentum is 17550 kg·m/s towards the wall.