Answer:
2a) x = 32 [mil/h]; 2b) t = 0.5[h]; 3a) t = 2.5 [h]; 3b) x = 185[mil]
Step-by-step explanation:
2a)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
![v=(x)/(t) \\v=velocity [(mil)/(h) ] = 32 [(mil)/(h)] \\t=time = 1 [h]\\x=v*t\\x=32[(mil)/(h) ]*1[h]\\x=32[mil}](https://img.qammunity.org/2021/formulas/physics/college/b8dybkhovnnl70rni02y1iu8rc6z4mgju3.png)
2b)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
![v=(x)/(t) \\t=(x)/(v) \\t=(420)/(840)\\ t=0.5[h]](https://img.qammunity.org/2021/formulas/physics/college/4u41mq9z1jl9jj9hg66ldlakkn04xc6099.png)
3a)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
![v=(x)/(t) \\t=(x)/(v) \\t=(35)/(14)\\ t=2.5[h]](https://img.qammunity.org/2021/formulas/physics/college/9c30pjrarkt1uypu9oqs1l4k3fcgjvxhph.png)
3b)
We can solve this problem by using the kinematics equation, which relates speed to time and displacement.
![v=(x)/(t) \\v=velocity [(mil)/(h) ] = 74 [(mil)/(h)] \\t=time = 2.5 [h]\\x=v*t\\x=74[(mil)/(h) ]*2.5[h]\\x=185[mil}](https://img.qammunity.org/2021/formulas/physics/college/99vm32jsarkzbwfu235oz8a2solyhfc5lo.png)