The length of segment CF is 15
Explanation:
Let = ABEC = 133
Let = ABFD = 140
Let A = ABFC = 161
Let = A = 8 AD
Let x = CF
+ = A +
133 + 140 = 161 +
= 133 + 140 - 161
= 122 = 8AD
8AD = 122
AD=
AD=14
A= × AD
161 = ×14
161 = (8 + x )×7
23 = 8 + x
x = 23 - 8
x= 15
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