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A block of mass 5 kg is descending with a constant velocity on an inclined plane at 30°. What is the value of the frictional force?
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A block of mass 5 kg is descending with a constant velocity on an inclined plane at 30°. What is the value of the frictional force?

User Robert Claypool
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1 Answer

5 votes

Answer:28.9N

Step-by-step explanation:

F=UR R=mg R=5×10 R=50N

U=tan© U=Tan30 U=1/√(3)

F=UR F=1/√(3) ×50

F=28.9N

User Martins Untals
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