Answer:
option A
Step-by-step explanation:
given,
speed of car 1 = 100 Km/s
speed of car 2 = 50 Km/s
final speed = 0 Km/s
now,
skid mark when the car is moving at 100 Km/s
using equation of motion
v² = u² + 2 a s₁
0² = 100² - 2 a s₁
100² = 2 a s₁
..........(1)
now,
skid mark when the car is moving at 50 Km/s
using equation of motion
v² = u² + 2 a s₂
0² = 50² - 2 a s₂
50² = 2 a s₂
..........(2)
dividing equation (1)/ (2)
![(s_1)/(s_2) = (100^2)/(50^2)](https://img.qammunity.org/2021/formulas/physics/college/da4vh6nywxg2rg23mjgwtca4pkv15oy0za.png)
![(s_1)/(s_2) =4](https://img.qammunity.org/2021/formulas/physics/college/8u414gueut7c34ncukbtcdzmdn3zhq1tma.png)
s₁ = 4 s₂
Hence, the skid mark for 100 Km/s is four time as far as 50 Km/s
The correct answer is option A