Answer:
![m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s](https://img.qammunity.org/2021/formulas/physics/high-school/ecw6wgfea6ru0s0rkkgqrmgwfsa85692vd.png)
Step-by-step explanation:
Conservation of Momentum
The total momentum of a system of two particles is
![p=m_1v_1+m_2v_2](https://img.qammunity.org/2021/formulas/physics/high-school/z0qc50ohxl6rck3h4bd8oqce263mbfyjr7.png)
Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now
![p'=m_1v_1'+m_2v_2'](https://img.qammunity.org/2021/formulas/physics/high-school/jvf4w5vcjqpbgza9svgu4g6kfyr2v3xdco.png)
The momentum is conserved if no external forces are acting on the system, thus
![m_1v_1+m_2v_2=m_1v_1'+m_2v_2'](https://img.qammunity.org/2021/formulas/physics/high-school/h4eg0bnzfesmsdq1cgbrcsvn30v768yi0i.png)
Let's put some numbers in the problem and say
![m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s](https://img.qammunity.org/2021/formulas/physics/high-school/ecw6wgfea6ru0s0rkkgqrmgwfsa85692vd.png)
![(8)(12)+(6)(4)=(8)(-6)+(6)(28)](https://img.qammunity.org/2021/formulas/physics/high-school/o2g1gm5irmae836yrr7m8xlgsb3ribz4g6.png)
![96+24=-48+168](https://img.qammunity.org/2021/formulas/physics/high-school/d95aqfkzovyp3iu13v5tfmcre2i9x6rwax.png)
120=120
It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s