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Provide an example of when momentum is conserved and explain your answer you can get 10 PTS if answered with a good explaination

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Answer:


m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

Step-by-step explanation:

Conservation of Momentum

The total momentum of a system of two particles is


p=m_1v_1+m_2v_2

Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now


p'=m_1v_1'+m_2v_2'

The momentum is conserved if no external forces are acting on the system, thus


m_1v_1+m_2v_2=m_1v_1'+m_2v_2'

Let's put some numbers in the problem and say


m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s


(8)(12)+(6)(4)=(8)(-6)+(6)(28)


96+24=-48+168

120=120

It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s

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