Question

Solving the right triangle ‼️ (Round to the nearest tenth) can someone help me find A,a, and b❓

Answer 1

see explanation

Explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 angles from 180 for A

A = 180° - (50 + 90)° = 180° - 140° = 40°

Use the cosine and sine ratios in the right triangle for a and b

cos50° =
`(adjacent)/(hypotenuse)` =
`(a)/(26)`

Multiply both sides by 26

26 × cos50° = a, thus

a ≈ 16.7 ( to the nearest tenth )

sin50° =
`(opposite)/(hypotenuse)` =
`(b)/(26)`

Multiply both sides by 26

26 × sin50° = b, thus

b ≈ 19.9 ( to the nearest tenth )

Answer 2

A is 40 degrees imma edit this or do it in comments the other ones