Question

PLEASE HURRY THANK YOU

The tree diagram below shows all of the possible outcomes for flipping three coins.

A tree diagram has outcomes (H, H, H), (H, H, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T).

What is the probability of one of the coins landing on tails and two of them landing on heads?
1/4
3/8
1/2
3/4

Answer 1

Option B

The probability of one of the coins landing on tails and two of them landing on heads is
`(3)/(8)`

Solution:

To find: probability of one of the coins landing on tails and two of them landing on heads

The probability of an event is given as:

`probability =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}`

The outcomes are given as:

(H, H, H), (H, H, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T)

Here, total number of possible outcomes = 8

Favorable outcomes = one of the coins landing on tails and two of them landing on heads

Favorable outcomes = (H, H, T) , (H, T, H) , (T, H, H)

Therefore, number of favorable outcome = 3

Thus probability is given as:

`probability = (3)/(8)`

Thus option B is correct