Question

A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 5 tables is $48. The total cost to rent 6 chairs and 2 tables is $30. What is the cost to rent each chair and each table?

Cost to rent each chair:$
Cost to rent each table:$

Answer 1

The answer to your question is Table = $8.25; Chair = $2.25

Explanation:

Chair = C

Table = T

To solve this problem we need to write two equations and solve the system.

Equation 1 3C + 5T = $48

Equation 2 6C + 2T = $30

Solve then by Elimination

Multiply equation 1 by 2 6C + 10T = 96

Multiply equation 2 by -5 -30C - 10T = -150

-24C 0 = -54

C = -54 / -24

C = $2.25

Substitute C in Equation 1 3(2.25) + 5T = 48

27/4 + 5T = 48

5T = 48 - 27/4

5T = 165/4

T = 165/20

T = 33/4 = $8.25

Answer 2

Answer:the cost of renting one chair is $2.25

the cost of renting one table is $8.25

Explanation:

Let x represent the cost of renting one chair.

Let y represent the cost of renting one table.

The total cost to rent 3 chairs and 5 tables is $48. This means that

3x + 5y = 48 - - - - - - - - - -1

The total cost to rent 6 chairs and 2 tables is $30. This means that

6x + 2y = 30 - - - - - - - - - -2

Multiplying equation 1 by 6 and equation equation 2 by 3, it becomes

18x + 30y = 288

18x + 6y = 90

Subtracting, it becomes

24y = 198

y = 198/24 = 8.25

Substituting y = 8.25 into equation 1, it becomes

3x + 5 × 8.25 = 48

3x + 41.25 = 48

3x = 48 - 41.25 = 6.75

x = 6.75/3 = 2.25