Question

A ball is dropped from a height of 80m. The time, in seconds, it takes to reach the ground is:__________.

Answer 1

4.04 s

Step-by-step explanation:

h = vi + 1/2 a t ^2

HERE h = 80 m , vi = 0 , a =9.81 m/s^2

80 = 0 + 1/2 × 9.81 × t ^2

80 = 4.905 t^2

t^2 = 80/4.905

t ^2 = 16.30988

t = square root of 16.30988

t = 4.0385 s

t = 4.04 s