Question

A circuit contains a capacitor and a resistor connected in series. Of the circuit's capacitive reactance measured 650 Ω and its resistance measures 1,200 Ω, what is the phase angle between circuit voltage and current?

Answer 1

Ф = 28.41°

Step-by-step explanation:

Given that

Capacitive reactance ,Xc = 650 Ω

Resistance ,R= 1200 Ω

As we know that phase angel Ф given as

`tan\phi =(X_c)/(R)`

Now by putting the values

`tan\phi =(X_c)/(R)`

`tan\phi =(650)/(1200)`

tanФ = 0.541

Now by taking inverse

`\phi=tan^(-1)0.541`

We get

Ф = 28.41°

Therefore the answer will be 28.41°.