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World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15m/s^2 .

Part A
How much horizontal force F must a sprinter of mass 64 kg exert on the starting blocks to produce this acceleration?
Express your answer in newtons using two significant figures.

Part B
Which body exerts the force that propels the sprinter, the blocks or the sprinter?
Which body exerts the force that propels the sprinter, the blocks or the sprinter?

1 Answer

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Answer:

A. The force exerted by the sprinter must be 9.6 × 10² N.

B. The force that propels the sprinter is exerted by the blocks.

Step-by-step explanation:

Hi there!

Let´s begin with part B:

The sprinter exerts a force on the blocks and, as a reaction, the blocks exert a force on the sprinter that is of equal magnitude but opposite direction (Newton´s third law). This reaction of the blocks causes the acceleration of the sprinter.

Part A

The force exerted by the blocks can be calculated using Newton´s second law:

F = m · a

Where:

F = exerted force.

m = mass of the object being accelerated.

a = acceleration of the object after applying the force on the object.

F = m · a

F = 64 kg · 15 m/s²

F = 9.6 × 10² N

User Ensom Hodder
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