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Solve 8 = 2^x+4

X=-4
X=-1
X=0
X=7

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1 Answer

6 votes

Answer:

  • as written, x = 2
  • as interpreted, x = -1

Explanation:

To solve the problem as written, subtract 4, then take the logarithm base 2.

4 = 2^x

2^2 = 2^x

2 = x . . . . . . logarithm base 2

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Because this is not an answer choice, we suspect your problem is really ...

8 = 2^(x+4) . . . . . . parentheses are required

2^3 = 2^(x+4) . . . . show 8 as a power of 2

3 = x+4 . . . . . . . . . take the log to the base 2 (equate exponents)

-1 = x . . . . . . . . . . . subtract 4

User Muzzamo
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