Question

What are the observation when hydrogen sulphide passes throughK2CR2O7​

Answer 1

Potassium Dichromate(K2Cr2O7) is oxidising agent and will oxidise Hydrogen sulfide(H2S) to Sulphur(S).

The orange color of Potassium dichromate is changed to green due formation of Chromium sulphate.

Step-by-step explanation:

The balance chemical equation for the reaction is :

`K_(2)Cr_(2)O_(7) + 3H_(2)S + 4H_(2)SO_(4)\rightarrow`
`Cr_(2)(SO_(4))_(3) + 3S + K_(2)SO_(4) +7H_(2)O`

K2Cr2O7 = It is the commonly used inorganic reagent used for its oxidizing properties .It is crystalline , bright orange coloured.

In this reaction it oxidise Hydrogen sulfide to sulfate .

Hydrogen Sulfide = It has Formula H2S . It is a colourless gas .

It is foul smelling and act as reducing agent .

In this reaction H2S reduces Potassium dichromate(Cr = +6) to Chromium Sulfate (Cr = +3)