Question

1) Given the balance equation below. Calculate how much Na3PO4 in grams you

would need to create 100 grams of NaOH.
1 Na3PO4 + 3 KOH → 3 NaOH + 1 K3PO4​

Answer 1

136.67 g of Na3PO4 is required to create 100 gram of NaOH.

Step-by-step explanation:

The balanced equation:

`Na_(3)PO_(4) + 3 KOH \rightarrow 3 NaOH + K_(3)PO_(4)`

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

or

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

`(164)/(120)`

100 grams of NaOH is produced from =

`(164)/(120)*100` gram of Na3PO4

calculate,

= 136.67 g