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1 vote
A fish tank, in a shape of rectangular prism, measures

100 cm × 60 cm × 40 cm. The water level reached the
midpoint of the base (the 50 cm mark), when the tank
was tilted to rest on a 60 cm edge, as shown in the
diagram on the right. What would be the depth of the
water, if the tank is returned to its horizontal position
(resting on its 60 cm × 100 cm base)?

User Bao Nguyen
by
8.6k points

2 Answers

2 votes

Answer:20cm

Explanation:

User ChrisLively
by
8.1k points
3 votes

Answer:

The deep of the water would be 20 cm

Explanation:

step 1

Find the volume of the water

The volume of the water is equal to


V=LWH

we have


L=60\ cm\\W=40\ cm\\H=50/ cm

substitute


V=(60)(40)(50)


V=120,000\ cm^3

step 2

Find the deep of the water, if the tank is returned to its horizontal position

(resting on its 60 cm × 100 cm base)

Now we have


L=60\ cm\\W=100\ cm\\H=?\ cm


V=120,000\ cm^3

substitute the given values


120,000=(60)(100)H

solve for H


H=120,000/6,000


H=20\ cm

therefore

The deep of the water would be 20 cm

User Atequer Rahman
by
8.0k points

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