Question

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $20 and same-day tickets cost $25 . For one performance, there were 75 tickets sold in all, and the total amount paid for them was $1700 . How many tickets of each type were sold?

Number of advance tickets sold:
Number of same day tickets sold:

Answer 1

Answer:the number of advance tickets sold is 35

the number of same day tickets sold is 40

Explanation:

Let x represent the number of advance tickets sold.

Let y represent the number of same day tickets sold.

For one performance, there were 75 tickets sold in all. This means that

x + y = 75

Advance tickets cost $20 and same-day tickets cost $25. The total amount paid for them was $1700 both tickets. This means that

20x + 25y = 1700 - - - - - - - - - - - 1

Substituting x = 75 - y into equation 1, it becomes

20(75 - y) + 25y = 1700

1500 - 20y + 25y = 1700

- 20y + 25y = 1700 - 1500

5y = 200

y = 200/5 = 40

substituting y = 40 into x = 75 - y, it becomes

x = 75 - 40

x = 35