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In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

User Nick Sloan
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1 Answer

1 vote

Answer:


(4)/(5)

Explanation:

Given: There are 2 classes of 25 students.

13 play basketball

11 play baseball.

4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)=
(13)/(25) +(11)/(25) -(4)/(25)

taking LCD as 25 to solve.

⇒P(a∪b)=
(13* 1+11* 1-4* 1)/(25) = (20)/(25)

∴ P(a∪b)=
(4)/(5)

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is
(4)/(5).

User Mzk
by
8.7k points

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