Answer:
![(\pi d^2)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/di3hn6qq7991es692creugc776dwoti600.png)
Explanation:
Semicircle is HALF of a circle. The area of a circle is given by:
![\pi r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/dlcbuo3stzuipxv6p7f7yl1stpzfah0aij.png)
So, area of semi circle is:
![(\pi r^2)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ln3o3wrcwc8h5agiqyf3wkj8w7110w6yu1.png)
Where r is the radius (half of diameter).
The diameter is given as "d", so the radius is half of that, this would be:
![(d)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ylu6ff6jppgchbuk6zhhrtj1tdam1upkam.png)
Now, substituting this into "r", we get the expression for area of the semicircle:
Area =
![(\pi r^2)/(2)=(\pi ((d)/(2))^2)/(2)=(\pi ((d^2)/(4)))/(2)=((\pi d^2)/(4))/(2)=(\pi d^2)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ng412a32u70j7m9b6ypl9y1o4ca7y8xg8w.png)
This is the area.