Question

PLEASE HELP AS FAST AS YOU CAN PLEASE

one mixture contains 6 fluid ounces of water and 10 ounces of vinegar. A second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar. Are the mixtures proportional? If not, how much water or vinegar would you add in the second mixture so that they are proportional?

Answer 1

The mixtures are not proportional.

3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.

Explanation:

The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.

Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5

Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.

Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4

Therefore, the mixtures are not proportional.

Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.

So,
`(9)/(12 + x)  = (6)/(10)`

⇒ 12 + x = 15

⇒ x = 3 fluid ounces.

Therefore, 3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture. (Answer)