How to solve -16x+2y=-2, y=8x-1 by using substitution

Question

asked Aug 3, 2021 129k views

1 Answer

Berna · Answer 1 · 2021-08-06T16:36:46+0000

For this case we have the following system of equations:

$-16x + 2y = -2\\y = 8x-1$

To solve, we substitute the second equation in the first:

-16x + 2 (8x-1) = - 2

We apply distributive property to the terms within parentheses:

$-16x + 16x-2 = -2\\-2 = -2$

Equality is met, so for any value of x it will be fulfilled. Therefore, the system of equations has infinite solutions.

Answer:

Infinite solutions