Question

On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1

Answer 1

Explanation:

its B just took the quiz

y ≥ One-thirdx − 1

Answer 2

`y\geq(1)/(3)x-1`

Explanation:

A solid straight line has a positive slope and goes through (0, negative 1) and (3, 0)

Find the slope of the solid line

`m=(0+1)/(3-0)\\\\m=(1)/(3)`

The equation of the solid line in slope intercept form is equal to

`y=mx+b`

we have

`m=(1)/(3)`

`b=-1` ---> given problem

substitute

`y=(1)/(3)x-1`

Everything above and to the left of the line is shaded

so the inequality is equal to

`y\geq(1)/(3)x-1`