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If positive integer x is a multiple of 6 and positive integer y is a multiple of 14, is xy a multiple of 105?(1) x is a multiple of 9.(2) y is a multiple of 25.

User Aung Thiha
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2 Answers

2 votes

Answer:

The statement 2 alone is sufficient.

Explanation:

Using the Arithmetic Properties of numbers we have

Given that x is a multiple of 6, x has at least 1 factor of 2 and at least 1 factor of 3. Given that y is a multiple of 14, y has at least 1 factor of 2 and at least 1 factor of 7. So, xy has at least 1 factor of 2, at least 1 factor of 3, and at least 1 factor of 7 and can be expressed as xy = (2)(3)(7)r = 42r, where r is a positive integer. Determine if xy is a multiple of 105 = (3)(5)(7).

1) If x = (2)(3)(3), then x is a multiple of both 6 and 9. If y = (2)(7) then y is a multiple of 14. In this case, xy = (2)(3)(3)(2)(7) = (2²)(3²)(7) and is not a multiple of 105. However, if x = (2)(3)(3)(5), then x is a multiple of both 6 and 9. If y = (2)(7), then y is a multiple of 14. In this case, xy =(2)(3)(3)(5)(2)(7) = (2²)(3²)(5)(7) and is a multiple of 105; NOT SUFFICIENT.

2) If y = (2)(5)(5)(7), then y is a multiple of 14 and 25. If x is a multiple of 6, x = (2)(3)q for some positive integer q. Then xy = (2)(3)q(2)(5)(5)(7) = (2)(2)(3)(5)(5)(7)q and xy is a multiple of 105; SUFFICIENT.

The statement 2 alone is sufficient.

User Jay Truluck
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8.5k points
5 votes

Answer:

x = 30 is a multiple of 6

y = 28 is a multiple of 14

xy = 840 is a multiple of 105

(1) x = 45 is a multiple of 9

(2) y = 525 is a multiple of 25

xy = 23,625 is a multiple of 105

Explanation:

x = 30 is a multiple of 6

y = 28 is a multiple of 14

xy = 30 × 28 = 840 is a multiple of 105

(1) x = 45 is a multiple of 9

(2) y = 525 is a multiple of 25

xy = 45 × 525 = 23,625 is a multiple of 105

User TTCG
by
8.2k points

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