Question

A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much electric power does the power plant output?

Answer 1

P₀ = 5.76 x 10⁻² MW

Step-by-step explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

`\eta = (P_0)/(P)`

where P is the power produced in the power plant

P₀ is the power output of the power plant

`\eta = (P_0)/(P)`

`0.32 = (P_0)/(0.18)`

P₀ = 0.18 x 0.32

P₀ = 0.0576 MW

P₀ = 5.76 x 10⁻² MW

Power plant output is equal to P₀ = 5.76 x 10⁻² MW