Answer: Therefore, the x-intercept of the line is 0
A line with slope 2/3 contains the point P(-18, -12). What is the x intercept of the line?
Explanation:
Given;
Slope m = 2/3
Straight line equation is given as
y = mx+c
Where m = slope and c = intercept on y axis
For this case,
y = 2/3x + c .....1
At point (-18,-12), Eqn 1 becomes;
-12 = 2/3(-18) + c
-12 = -12 + c
c = 0
The straight line equation becomes
y = 2/3x + 0
Therefore at y = 0 the value of x = 0
Therefore the intercept is at (0,0)
Therefore, the x-intercept of the line is 0