Question

12. The sum of three consecutive integers is 12 more than twice the largest integer. Which of the following

equations could be used to find the three integers?

(1) n+n+1+n+2 = 2n +2+12
(2) n+n+2+n+4 = 2(n + 4)+12
(3) n+n+1+n+3 = 2n +3+12
(4) n+n+1+n+2 = 2(n + 2) +12​

Answer 1

OPTION 4

Explanation:

Let the three consecutive numbers be n, (n + 1) and (n + 2).

Note that the largest number of the three is (n + 2) and the smallest is n.

So, according to the given data, the sum of all the three integers is equal to 1 more than twice more than the largest number.

Writing it mathematically, we have:

n + (n + 1) + (n + 2) = 12 + 2(n + 2)

This is OPTION (4) and is the answer,