Answer:
option D
Step-by-step explanation:
given,
mass of the freight car (m) = 5,000 Kg
initial speed of car (u)= 2 m/s
mass of the freight car (M)= 10,000 Kg
initial speed (u')= 0 m/s
speed after collision (V)= ?
using conservation of momentum
m u + M u' = (M + m) V
5000 x 2 + 10000 x 0 = (5000 + 10000) V
![V = (10000)/(15000)](https://img.qammunity.org/2021/formulas/physics/high-school/dojo3c48hu01se2o3fm12vrnt5x926p2fj.png)
![V = (10)/(15)](https://img.qammunity.org/2021/formulas/physics/high-school/uzkmi5vvyxqbsnyabhl8k7n8853ebsubxe.png)
![V = (2)/(3)](https://img.qammunity.org/2021/formulas/physics/high-school/kzgxshjy0ydwwcuzhlc9gxa1g7hsfsyxns.png)
couples move away with the speed of
![V = (2)/(3)](https://img.qammunity.org/2021/formulas/physics/high-school/kzgxshjy0ydwwcuzhlc9gxa1g7hsfsyxns.png)
Hence, the correct answer is option D