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Solve the compound inequality: 1 < 3x - 2 < 10

User Jeniece
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1 Answer

1 vote

For this case we have the following inequality:


1 <3x-2 <10

Adding 2 on all three sides and inequality we have:


1 + 2 <3x-2 + 2 <10 + 2\\3 <3x <12

We divide the three sides of inequality by 3:


\frac {3} {3} <\frac {3x} {3} <\frac {12} {3}\\1 <x <4

Thus, the solution is given by the values of "x" between 1 and 4 without including 1 and 4. That is:


(1,4)

Answer:

The solution is given by x: (1,4)

User Sherah
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