Question

Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely with 196 grams of H2 SO4?

A) 1
B) 2
C) 0.5
D) 4

Answer 1

4 moles, 160 g

Step-by-step explanation:

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

For
`H_2SO_4`:-

Mass of
`H_2SO_4` = 196 g

Molar mass of
`H_2SO_4` = 98 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (196\ g)/(98\ g/mol)`

`Moles\ of\ Sulfuric\ acid= 2\ mol`

According to the given reaction:

`2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O`

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

Mass = Moles*molar mass =
`4* 40\ g` = 160 g