Answer:
1. Radius: 30 yards
2. Cost per square yard: $7,065
Explanation:
The formula to find the area of quarter circle is:
![A=(\pi r^2)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/m1kbhmz81szi0s06ucbzhbwv06ay9tsw5i.png)
Where "r" is the radius.
Solving for "r":
![r=\sqrt{(4A)/(\pi)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/3iv4o3lfe7f3c6rfizv3ct3fu13xuehqtk.png)
1. Find the area of the playground with the formula for calculate the area of a square:
![A=s^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/o9zxg41yvoa3srjrnclaalypba9y5e71gu.png)
Where "s" is the side lenght.
Since:
![s=109\ yd](https://img.qammunity.org/2021/formulas/mathematics/high-school/li643iuerp14w2atp5uqonz0t90q803xi8.png)
You get:
![A_1=(109\ yd)^2=11,881\ yd^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/iowwlq047nmdnd6qxw5v13a2qhgmxr22j7.png)
All the skating rings are equal.
So, knowing that the area of the remaining field is:
![A_3=9,055\ yd^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/wka18cr7cb57m9t4jscm5b6w4avxvodwnf.png)
The sum of the areas of all the quarter circles is:
![A_4=11,881\ yd^2-9,055\ yd^2=2,826\ yd^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/3appzy00ho8d4g66slp6rrvb70zfe8oo3c.png)
To find the area of each skating ring, divide that result by 4:
![A_4=(2,826\ yd^2)/(4)= 706.5\ yd^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/sloq6f3maig3d88g7qlb5qktn90glyaubi.png)
Then, the radius is:
![r=\sqrt{(4(706.5\ yd^2))/(3.14)}=30\ yd](https://img.qammunity.org/2021/formulas/mathematics/high-school/fud2iwmnw3midfkgagpcaxknqz8bp4x7k3.png)
2. Mulitply the total area of the skating rings by $2.50 in order to find the cost of cementing the skating rings per square yard:
![Cost\ per\ square\ yard=2,826*\$2.50=\$7,065](https://img.qammunity.org/2021/formulas/mathematics/high-school/u53t0fkie2yint0e6xyaoxu895b84f2r6n.png)