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You have landed on an unknown planet, Newtonia, and want to know what objects weigh there. When you push a certain tool, starting from rest, on a frictionless horizontal surface with a 12.0-N force, the tool moves 16.0 m in the first 2.00 s. You next observe that if you release this tool from rest at 10.0 m above the ground, it takes 2.58 s to reach the ground. What does the tool weigh on Newtonia, and what does it weigh on Earth?

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Answer:

Step-by-step explanation:

Given

Force applied
F=12\ N

time taken
t_1=2\ s

Displacement
s=16\ m

using


s=ut+(1)/(2)at^2

u=initial velocity

s=displacement

t=time


16=0+(1)/(2)a(2)^2


a=8\ m/s^2

thus mass of body
m=(F)/(a)=(12)/(8)=1.5\ kg

Next it is released from a height of
h=10\ m

time taken to reach ground
t_2=2.58\ s

using
s=ut+(1)/(2)at^2 in vertical direction

here acceleration is due to acceleration due to gravity(g') of the planet

as it at rest so u=0 here


10=0+(1)/(2)(g')(2.58)^2


g'=3.004\ m/s^2

Thus acceleration due to gravity on Newtonian is
3\ m/s^2

Weight of tool on Newtonia
W'=mg'


W'=1.5* 3.004=4.506\ N

Weight on Earth
W=1.5* 9.8=14.7\ N

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