Question

Crickets Chirpy and Milada jump from the top of a vertical cliff. Chirpy drops downward and reaches the ground in 2.70 s, while Milada jumps horizontally with an initial speed of 95.0 cm/s. How far from the base of the cliff will Milada hit the ground? Ignore air resistance.

Answer 1

Step-by-step explanation:

Given

Time taken to reach ground is
`t=2.7\ s`

Malda initial velocity
`u=95\ cm/s`

Let h be the height of Cliff

using
`h=ut+(1)/(2)at^2`

where, u=initial velocity

t=time

In first case chirpy drop downward thus u=0

`h=0+(1)/(2)(9.8)(2.7)^2`

`h=35.72\ m`

For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]

time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by

`R=u* t`

`R=0.95* 2.7=2.43\ m`