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A 3.00 kg toy falls from a height of 1.00 m. What will the kinetic energy of the toy be just before the toy hits the ground

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Answer:

K E = 29.4 J

Step-by-step explanation:

given,

mass of the toy = 3 Kg

height of fall = 1 m

acceleration due to gravity (g)= 9.8 m/s²

Kinetic energy of the toy = ?

Using conservation of energy

Potential energy of the toy at height h will be converted into into kinetic energy .

P E = K E

K E = m g h

K E = 3 x 1 x 9.8

K E = 29.4 J

Hence, the kinetic energy of the toy before it hit the ground is equal to K E = 29.4 J

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