Answer:
A) between 48% and 54%
Explanation:
given that a random sample of 1001 Americans aged 18-24 years showed that 51% believe their health is extremely important.
Here
Sample size n =1001
sample proportion p = 0.51
Standard error of proportion =

Since sample size is sufficiently large we can take Z critical value for confidence interval
Z critical value for 95% = 1.96
Margin of error = ±1.96*std error
= ±0.0310
confidence interval = 0.51 ±0.0310
= (0.48, 0.54)
i.e. A) between 48% and 54%