Question

Find the x-intercept of the line that is perpendicular to the

line 5x-25y+10=0 and passes through the point A(10,5).

Answer 1

y=-5x+6

Explanation:

The Slope is -5. And the Perpendicular slope is 1/5. Perpendicular equation y=mx+c Find c put in (0,-10) so -10=0/5+c so c=-10. so Perp eq is y=x/5–10 or x-5y=50