Question

Answer soon please! Question and answers are in the photograph attached.

Answer 1

Δ MLP ~ Δ HKG

By S-A-S similarity Postulate.

Explanation:

Given:

In Δ MLP

MP = 20 ,

LP = 15

∠ P = 42°

In Δ HKG

HG = 16 ,

KG = 12

∠G = 42°

To Prove:

Δ MLP ~Δ HKG

Proof:

In Δ MLP and Δ HKG

`(MP)/(HG)= (20)/(16)=(5)/(4)` ..........( 1 )

`(LP)/(KG)= (15)/(12)=(5)/(4)` ..............( 2 )

∴
`(MP)/(HG)=(LP)/(KG)` ...From 1 and 2

∠P ≅ ∠ G = 42° ...............Given

∴ Δ MLP ~Δ HKG ......{ By S-A-S similarity test}............Proved