Question

Nuri joins a game for a car. The rule is that Nuri picks one key from the box either A, B, or C. A box has two keys but only one can be used. B box has three keys but only one can be used. C box has two keys but none of them can be used.

What is the probability that Nuri can win the car?

Answer 1

Answer:0.277

Explanation:

Given there are three boxes i.e. A , B and C

Probability of selecting any box is
`P_1=(1)/(3)`

Box A contains 2 keys out of which is 1 is correct so Probability of selecting the right key is
`P_2=(1)/(2)`

Box B contains 3 keys out of which is 1 is correct so Probability of selecting the right key is
`P_3=(1)/(3)`

Box C contains 2 keys out of which is 1 is correct but we cannot use it so Probability of selecting the right key is
`P_4=0`

Probability of selecting the right key is
`P=P_1* P_2+P_1* P_2+P_1* P_3`

`P=(1)/(3)* (1)/(2)+(1)/(3)* (1)/(3)+(1)/(3)* 0`

`P=(5)/(18)`

`P=0.277`