Question

A rectangle's length is 3.5 feet longer than its width. The perimeter of the rectangle is 58 feet. The width, w, can be found using the equation below.

2w+2(w+3.5)=58

Answer 1

The width of the rectangle is 12.75 feet

Explanation:

l = 3.5 + w

p= 58

p = 2w +2l

2w + 2(w + 3.5) = 58

2w + 2w + 7 = 58

4w + 7 = 58

4w = 51

w =12.75

Answer 2

For this case we have to:

w: Represents the width of the rectangle

L: Represents the length of the rectangle

Then, the perimeter is given by:

`P = 2w+2L`

According to the statement we have:

`L = 3.5+w\\P = 58`

Substituting we obtain the given equation:

`2w+2 (3.5 +w) = 58\\2w+7+2w = 58\\4w+7 = 58\\4w = 58-7\\4w = 51\\w = \frac {51} {4}\\w = 12.75`

Thus, the width of the rectangle is 12.75 feet

Answer:

The width of the rectangle is 12.75 feet