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Directions: Solve for area and perimeter in each of the following problems.

1) 17 yd

10 yd

2) 8 m

15 m

Directions: Solve for area and perimeter in each of the following problems. 1) 17 yd-example-1
User Acroscene
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2 Answers

17 votes
17 votes

Answer:

#1= perimeter=54 area=170

#2= perimeter=46 area=120

Explanation:

17+17+10+10=54

8+8+15+15=46

17x10=170

8x15=120

User Stmatengss
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25 votes
25 votes

Answer:

Area of a rectangle = width x length

Perimeter of a rectangle = (2 x width) + (2 x length)

1) Area = 10 x 17 = 170 yd²

Perimeter = (2 x 10) + (2 x 17) = 20 + 34 = 54 yd

2) Area = 8 x 15 = 120 m²

Perimeter = (2 x 8) + (2 x 15) = 16 + 30 = 46 m

User Jordon Willis
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