Question

A 15.85g piece of iron absorbs 1086.75 joules of heat energy and its temperature changes from 25 degrees Celsius to 175 degrees celcius. Calculate the specific heat capacity of iron.

Answer 1

Step-by-step explanation:

Specific heat capacity of iron is the amount of heat required to raise 1g of iron by 1 degree Celsius.

The formula is Q=mc∆T

Where Q is energy in joules.

M is mass in gram.

C is specific heat capacity in J/g°C.

∆T is change in temperature in degree Celsius

Q=1086.75joules

M=15.85g

C=?

∆T = final T-initial T(175-25)=150°c.

Q=Mc∆T

1086.75= 15.85×C×150

1086.85=2377.5c

C=1086.85÷2377.5

C=0.46J/g°C.