Question

Simplify x0y-3/x2y-1 A.1/x2y2 B. Y/x6 C. 4y3/x3 D.y3/2

Answer 1

Option A)
`(1)/(x^2y^2)` is correct.

Therefore the simplified given expression
`(x^0y^(-3))/(x^2y^(-1))=(1)/(x^2y^2)`

Explanation:

Given expression is
`(x^0y^(-3))/(x^2y^(-1))`

To simplify the given expression:

`(x^0y^(-3))/(x^2y^(-1))`

Above expression can be written as

`(x^0y^(-3))/(x^2y^(-1))=((1)y^(-3))/(x^2y^(-1))`

(since
`x^0=1` ,anything variable to the power "0' is 1)

`(x^0y^(-3))/(x^2y^(-1))=(y^(-3))/(x^2y^(-1))`

`(x^0y^(-3))/(x^2y^(-1))=(1)/(x^2y^(-1)y^3)` (since
`a^(-m)=(1)/(a^m)` )

`(x^0y^(-3))/(x^2y^(-1))=(1)/(x^2y^(-1+3))` (using the property
`a^m+a^n=a^(m+n)`)

`(x^0y^(-3))/(x^2y^(-1))=(1)/(x^2y^2)`

Therefore
`(x^0y^(-3))/(x^2y^(-1))=(1)/(x^2y^2)`

Therefore Option A)
`(1)/(x^2y^2)` is correct.

Therefore the simplified given expression
`(x^0y^(-3))/(x^2y^(-1))=(1)/(x^2y^2)`