Question

For which pairs of functions is (f circle g) (x)?

f (x) = x squared and g (x) = StartFraction 1 Over x EndFraction
f (x) = StartFraction 2 Over x EndFraction and g (x) = StartFraction 2 Over x EndFraction
f (x) = StartFraction x minus 2 Over 3 EndFraction and g (x) = 2 minus 3 x
f (x) = one-half x minus 2 and g (x) = one-half x + 2
Mark

Answer 1

I just took the test and aint gon cap i guessed on it but the answer is B.

f(c)=2/x and g(x)=2/x

sorry I late but i thought i should still tell

Explanation:

Answer 2

Option B is correct. The required composite function where f(g(x)) is x is f (x) = StartFraction 2 Over x EndFraction and g (x) = StartFraction 2 Over x EndFraction

Composite functions are functions written inside another function e.g f(g(x))

Given the expressions

f(x) = 2/x

g(x) = 2/x

We are to find the composite function f(g(x))

f(g(x)) = f(2/x)

f(2/x) = (2/(2/x))

f(2/x) = 2 * x/2

f(2/x) = x

Hence the required composite function where f(g(x)) is x is f (x) = StartFraction 2 Over x EndFraction and g (x) = StartFraction 2 Over x EndFraction