Question

What is the area of the new trapezoid formed by dilating the original by a factor of 3

Answer 1

`A_(new)=9A_(original)`

Explanation:

The are of a trapezoid is:

`A_(original)=((a+b))/(2)h`

where:

• a and b are bases
• h is the height

When a geometric figure dilates, every coordinate of the original figure must be multiplied by the scale factor of this dilatation. In our case this factor is 3, therefore we will have:

`A_(new)=((3a+3b))/(2)3h`

`A_(new)=9((a+b))/(2)h`

`A_(new)=9A_(original)`

The new area is 9 times the original one.

I hope it helps you!