Question

The density, rho, of sea-water is 1.2 × 103 kg m−3. Using the expression Wave Power Equation, estimate the gravitational power per metre length available in a wave of height 0.60 m.

Answer 1

E = 529.2 Joules

Step-by-step explanation:

The gravitational power can be calculated as:

`E = (\rho gA^(2) )/(2)`

Where ρ: Sea- water density

A: is the amplitude of the wave (that is to say half its height H)

g: the gravitational acceleration

Then

`E = ((1200)(9.8)(0.3^(2)) )/(2)`

E = 529.2 Joules