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Can the positive integer p be expressed as the product of two integers, each of which is greater than 1? 1. 31 < p < 37 2. p is odd.

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Answer:

1)
31 < p<37

For this case the values that satisfy the inequality are: 32,33,34,35,36

And we can analyze one by one the number:


a=32= 16*2 so then is a composite number because 2>1 and 16>1


a=33= 11*3 so then is a composite number because 3>1 and 11>1


a=34= 17*2 so then is a composite number because 2>1 and 17>1


a=35= 7*5 so then is a composite number because 7>1 and 5>1


a=36= 6*6 so then is a composite number because 6>1 and 6>1

So then part 1 is correct and we can see that the statement is enough or sufficient all the values on 31<P<37 are composite numbers.

2) For this cas this statement is FALSE, since we have a counterexample on this case:


a=3=1*3 and 3 is not a composite number since 1 is not >1

And since we have one element that not satisfy the condition that's FALSE.

Explanation:

For this question we need to use the following definition "If an integer p can b expressed as the product of two integers, each of which that is greater then 1, then the integer p can be considered as a composite number". And this number is not the same as prime number.

Part 1


31 < p<37

For this case the values that satisfy the inequality are: 32,33,34,35,36

And we can analyze one by one the number:


a=32= 16*2 so then is a composite number because 2>1 and 16>1


a=33= 11*3 so then is a composite number because 3>1 and 11>1


a=34= 17*2 so then is a composite number because 2>1 and 17>1


a=35= 7*5 so then is a composite number because 7>1 and 5>1


a=36= 6*6 so then is a composite number because 6>1 and 6>1

So then part 1 is correct and we can see that the statement is enough or sufficient all the values on 31<P<37 are composite numbers.

Part 2

For this cas this statement is FALSE, since we have a counterexample on this case:


a=3=1*3 and 3 is not a composite number since 1 is not >1

And since we have one element that not satisfy the condition that's FALSE.

User Frederik Spang
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