Answer:
A) 36 g
Step-by-step explanation:
From the source, some values have been correct.
Given that;-
Mass of NaCl formed = 116 grams
Molar mass of NaCl = 58 g/mol
Moles of NaCl =
![(Mass)/(Molar\ mass)=(116)/(58)\ mol=2\ mol](https://img.qammunity.org/2021/formulas/chemistry/high-school/qxeu8dc93mwkw79e5mous2orzmpyn5ypjs.png)
According to the reaction shown below:-
![HCl+NaOH\rightarrow NaCl+H_2O](https://img.qammunity.org/2021/formulas/chemistry/high-school/jpaotmdezpzlrye5dy6cqcz4hqyfm9mtsr.png)
1 mole of NaCl and 1 mole of
are produced upon reaction.
So,
2 moles of NaCl and 2 moles of
are produced upon reaction.
Moles of water = 2 moles
Molar mass of water = 18 g/mol
Mass =
![Moles* Molar\ mass=2* 18\ g=36\ g](https://img.qammunity.org/2021/formulas/chemistry/high-school/81vq1x2huogor47mq5jguaqp2vp3gmb144.png)
36 g of
is produced.